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Tuesday, August 23, 2016

A vector of information equilibrium relationships


This is a mathematical interlude that looks at some geometric interpretations of an ensemble of information equilibrium relationships. It represents some notes for some future work.

Let's start with a vector of information equilibrium relationships between output in a given sector yi and the money supply pi:yim so that

dyidm=Aij(m)yj

The solution to this differential equation is

yi(m)=[expmmrefdmAij(m)]yj(mref)

if A(m)=K/m (i.e. if A(m1)A(m2)=A(m2)A(m1) but not generally, see Magnus expansion) so that

yi(m)=[exp(Kijlogmmref)]yj(mref)

The volume spanned by these vectors (spanning the economic output space) is

V=det

So that the infinitesimal volume added to the economy is

dV = \left( \log \frac{m}{m_{ref}} \right) \;\text{tr}\; K

*  *  *

Update 30 November 2016

Let me continue this a bit, putting it in a more useful form. Starting with the expression for V above:

V = \det \exp \left( K \log \frac{m}{m_{ref}} \right)

The \log factor is a scalar and can be pulled through the determinant, gaining a factor of n (the number of markets indexed with i above (p_{i} : y_{i} \rightleftarrows m), giving us:

\begin{align} V & = \exp \left( n\; \log \frac{m}{m_{ref}}\right) \det \exp K \\ & = \exp \left(n\; \log \frac{m}{m_{ref}} \;\text{tr}\; K \right) \\ & = \left(\frac{m}{m_{ref}}\right)^{n} \; \exp  \text{tr}\; K \end{align}

If m grows exponentially at some rate \mu then V will grow with rate v where

v = n \; \mu \; \text{tr}\; K


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