Log-linear form of a general information equilibrium model

Let's take a general information equilibrium model $P : A \rightleftarrows B$ with price $P$ information transfer index $k$ and log-linearize it. That notation is shorthand for the differential equation:

$$P \equiv \frac{dA}{dB} = k \; \frac{A}{B}$$

Define the variables $A \equiv a \; e^{\tilde{a}_{t}}$, $B \equiv b \; e^{\tilde{b}_{t}}$, and $P \equiv p \; e^{\tilde{p}_{t}}$. Substitution into the equation above yields

$$d\tilde{a}_{t} = k \; d\tilde{b}_{t}$$

or as a finite difference equation:

$$\tilde{a}_{t+1} - \tilde{a}_{t} = k \left( \tilde{b}_{t+1} - \tilde{b}_{t} \right)$$

The general solution to the differential equation gives us the formula for the price $P$ 

$$P = ck \left( \frac{B}{B_{ref}} \right)^{k-1}$$

Using the substitutions above, $B_{ref} \equiv b$, and a little algebra, we can show

$$\tilde{p}_{t} = \left( k - 1\right) \tilde{b}_{t} + \log k + c_{p}$$

where $c_{p}$ is a constant (parameter). Therefore ...

Log-linear information equilibrium relationship

$$\begin{align} \tilde{a}_{t+1} & = k \left( \tilde{b}_{t+1} - \tilde{b}_{t} \right) + \tilde{a}_{t}\\ \tilde{p}_{t} & = \left( k - 1\right) \tilde{b}_{t} + \log k + c_{p} \end{align}$$

for which we can define the notation $\tilde{p}_{t} : \tilde{a}_{t} \rightleftarrows \tilde{b}_{t}$.